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Old Nov 11th, 2010, 9:22 pm   #1 (permalink)
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Electrical Tech Heads- Help Work This Out.

Got a question for any electrical buffs.

Replacing a front indicator 23w 12 volt front bulb with 10w 12 volt, replacing a rear indicator 23w 12 volt bulb with LED indicator 0.6 w 12 volt LED.

So originally there is 46w on the system, now there is +/- 10.6w so I have a difference of 35.4w.

Can any tell me what size resistor in ohms and watts that I need to balance the system and make it flash normally?

I have limited electrical knowledge hence my ask?

Cheers gents
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Old Nov 11th, 2010, 10:06 pm   #2 (permalink)
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What is the current of the LED and the voltage drop.
Subtract that voltage drop from 12 --> aV

R=aV /Current
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Old Nov 11th, 2010, 10:24 pm   #3 (permalink)
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Sorry I think I am talking crap.
I fixed this on my old hyper and I had a circuit diagram obtained from this site, but can't find it until I get home.
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Old Nov 11th, 2010, 10:27 pm   #4 (permalink)
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you just need a $10 load equalizer and all will be fine
comes with most good led kits

Quote:
Originally Posted by Monstaman View Post
Got a question for any electrical buffs.

Replacing a front indicator 23w 12 volt front bulb with 10w 12 volt, replacing a rear indicator 23w 12 volt bulb with LED indicator 0.6 w 12 volt LED.

So originally there is 46w on the system, now there is +/- 10.6w so I have a difference of 35.4w.

Can any tell me what size resistor in ohms and watts that I need to balance the system and make it flash normally?

I have limited electrical knowledge hence my ask?

Cheers gents
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Old Nov 11th, 2010, 10:43 pm   #5 (permalink)
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Resistor is connected across the LED
LED load resistors, wiring diagram

To sink 35W would require a very large resistor.
I think you need to see what is the minimum value required to stabilize rate and buy a ceramic wirewound type 5W type

Start with a 33 -50 Ohm
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Old Nov 12th, 2010, 1:01 am   #6 (permalink)
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Quote:
Originally Posted by Monstaman View Post
Got a question for any electrical buffs.

Replacing a front indicator 23w 12 volt front bulb with 10w 12 volt, replacing a rear indicator 23w 12 volt bulb with LED indicator 0.6 w 12 volt LED.

So originally there is 46w on the system, now there is +/- 10.6w so I have a difference of 35.4w.

Can any tell me what size resistor in ohms and watts that I need to balance the system and make it flash normally?

I have limited electrical knowledge hence my ask?

Cheers gents
Put the two 100ohm 5w resistors in parallel you have like I told you and that may work
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Old Nov 12th, 2010, 4:04 am   #7 (permalink)
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Quote:
Originally Posted by Monstaman View Post
Got a question for any electrical buffs.

Replacing a front indicator 23w 12 volt front bulb with 10w 12 volt, replacing a rear indicator 23w 12 volt bulb with LED indicator 0.6 w 12 volt LED.

So originally there is 46w on the system, now there is +/- 10.6w so I have a difference of 35.4w.

Can any tell me what size resistor in ohms and watts that I need to balance the system and make it flash normally?

I have limited electrical knowledge hence my ask?

Cheers gents
For which bike is it, it's not a Hyper.
Have you looked into this thread Blinker Idicator on Dash Not Working ? There you will find a circuit diagram and an example how to calculate the resistors.
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Old Nov 12th, 2010, 2:59 pm   #8 (permalink)
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23w / 14v = 1642 ma x 2 = 3284 ma or 3.3 amps total stock draw

10w / 14v = 714 ma new front draw

.6w / 14v = 43 ma new rear draw

3284 - (714 + 43) = 2527 ma difference from stock to moded draw

2527 ma x 14 = 35.4 Watts worth of additional resistor

35.4w / 14v = 2500ma
14v / 2500ma = 5.6 ohms worth of resistor

2 - 20 ohm / 20 watt resistors in parallel
will give you 10 ohms at 40 watts
Should be close enough
I think
You can try 10w resistors as they are easier to find but will get HOT so insulate well.
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Old Nov 14th, 2010, 2:03 pm   #9 (permalink)
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Quote:
Originally Posted by Mr Mike View Post
23w / 14v = 1642 ma x 2 = 3284 ma or 3.3 amps total stock draw

10w / 14v = 714 ma new front draw

.6w / 14v = 43 ma new rear draw

3284 - (714 + 43) = 2527 ma difference from stock to moded draw

2527 ma x 14 = 35.4 Watts worth of additional resistor

35.4w / 14v = 2500ma
14v / 2500ma = 5.6 ohms worth of resistor

2 - 20 ohm / 20 watt resistors in parallel
will give you 10 ohms at 40 watts
That is what I was thinking but the blue ones !!

Couldn't get any 20w resistors, think I will just get some No8 wire or a 4 inch nail.

Got some 5 w to play with but suspect they will end up just looking pretty on the shelf.
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Old Nov 14th, 2010, 4:56 pm   #10 (permalink)
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i need some electrical tech advice also, so thought I'd add myself to this thread.

Seems like since I unplugged my stock turn signals, that my front and rear lights (but not the passing trigger and not the brake light) intermittently stop working. I replace the 15v fuse and they work for awhile and then burn out.

Had ducshop install my oberon turn signals last week, and both lights went again... replaced the fuse, lights worked for a minute then went again.

any ideas what might be causing this?
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